Polar coordinates describe a point by its distance from the origin, ( r ), and its angle from the positive x-axis, ( theta ). To convert, use ( x = rcostheta ), ( y = rsintheta ). Conversely, use ( r^2 = x^2 + y^2 ), ( tantheta = frac{y}{x} ). A polar equation ( r = f(theta) ) gives r for each angle; the area it encloses is ( A = frac12int_alpha^beta r^2,dtheta ).
Rectangular coordinates ( (x, y) ) locate a point by going across and up. Polar coordinates ( (r, theta) ) locate it by turning and going out. Circles, spirals, petals and orbits that are awkward in x and y often have very simple polar equations. As a result, polar coordinates appear in precalculus, Calculus 2, physics and engineering.
Polar and rectangular conversions
| To find | Formula |
|---|---|
| x from ( (r, theta) ) | ( x = rcostheta ) |
| y from ( (r, theta) ) | ( y = rsintheta ) |
| r from ( (x, y) ) | ( r = sqrt{x^2 + y^2} ) |
| ( theta ) from ( (x, y) ) | ( tantheta = frac{y}{x} ), choosing the quadrant of ( (x, y) ) |
These come straight from the right triangle formed by the point, the origin and the x-axis: r is the hypotenuse (see trigonometric functions and the unit circle).

Example 1: polar to rectangular
( (3, frac{pi}{3}) ): ( x = 3cosfrac{pi}{3} = frac32 ) and ( y = 3sinfrac{pi}{3} = frac{3sqrt3}{2} approx 2.598 ). So the point is ( left( frac32, frac{3sqrt3}{2} right) ).
Example 2: rectangular to polar
( (1, 1) ): ( r = sqrt2 ) and ( tantheta = 1 ), with the point in Quadrant I, so ( theta = frac{pi}{4} ). The point is ( left( sqrt2, frac{pi}{4} right) ).
Example 3: watch the quadrant
( (-2, 2sqrt3) ): ( r = sqrt{4 + 12} = 4 ). ( tantheta = -sqrt3 ), and a calculator’s arctan gives ( -frac{pi}{3} ), which is in Quadrant IV. The point is in Quadrant II, so ( theta = pi – frac{pi}{3} = frac{2pi}{3} ). Answer: ( left( 4, frac{2pi}{3} right) ). This quadrant check is the most common source of errors (see inverse trig functions).
One point, many names
Unlike rectangular coordinates, a point has infinitely many polar names. ( (2, frac{pi}{6}) ), ( (2, frac{13pi}{6}) ) and ( (-2, frac{7pi}{6}) ) are the same point; a negative r means “go the opposite way”.
Converting equations
Rectangular to polar: substitute ( x = rcostheta ), ( y = rsintheta ).
- The circle ( x^2 + y^2 = 4x ) becomes ( r^2 = 4rcostheta ), so ( r = 4costheta ).
- The vertical line ( x = 3 ) becomes ( rcostheta = 3 ), so ( r = 3sectheta ).
Polar to rectangular: multiply through by r if that creates ( rcostheta ), ( rsintheta ) or ( r^2 ).
- ( r = 2sintheta ) becomes ( r^2 = 2rsintheta ), so ( x^2 + y^2 = 2y ): a circle of radius 1 centered at ( (0, 1) ).
Graphs of polar equations
| Equation | Graph |
|---|---|
| ( r = a ) | circle of radius ( a ) centered at the origin |
| ( theta = alpha ) | line through the origin at angle ( alpha ) |
| ( r = 2acostheta ) | circle of radius ( a ) through the origin, centered on the x-axis |
| ( r = 2asintheta ) | circle of radius ( a ) through the origin, centered on the y-axis |
| ( r = a(1 pm costheta) ) | cardioid (heart shape) |
| ( r = a + bcostheta ) | limaçon (with an inner loop if ( a < b )) |
| ( r = acos(ntheta) ) | rose: n petals if n is odd, 2n petals if n is even |
| ( r^2 = a^2cos 2theta ) | lemniscate (figure eight) |
| ( r = atheta ) | spiral of Archimedes |
How to sketch a polar graph
- Make a table of ( theta ) and r at the special angles ( 0, frac{pi}{6}, frac{pi}{4}, frac{pi}{3}, frac{pi}{2}, dots )
- Plot each point by turning to ( theta ) and going out r.
- Use symmetry: if replacing ( theta ) by ( -theta ) leaves the equation unchanged (as with cosine), the graph is symmetric about the x-axis.
- Find where ( r = 0 ): the graph passes through the origin there.
Example 4: the cardioid ( r = 1 + costheta ). At ( theta = 0 ), ( r = 2 ); at ( frac{pi}{2} ), ( r = 1 ); at ( pi ), ( r = 0 ) (the cusp at the origin); at ( frac{3pi}{2} ), ( r = 1 ). Also, it’s symmetric about the x-axis.

Slope of a polar curve
Treat ( x = r(theta)costheta ) and ( y = r(theta)sintheta ) as parametric equations in ( theta ). By the chain rule and product rule:

$$frac{dy}{dx} = frac{dy/dtheta}{dx/dtheta} = frac{r'sintheta + rcostheta}{r'costheta - rsintheta}$$
Example 5. For ( r = 1 + costheta ) at ( theta = frac{pi}{2} ): ( r = 1 ) and ( r’ = -sintheta = -1 ).
$$frac{dy}{dx} = frac{(-1)(1) + (1)(0)}{(-1)(0) - (1)(1)} = frac{-1}{-1} = 1$$
The tangent line at the point ( (0, 1) ) is ( y = x + 1 ) (see the equation of a tangent line). Horizontal tangents occur where ( frac{dy}{dtheta} = 0 ). Vertical tangents, however, occur where ( frac{dx}{dtheta} = 0 ).
Area in polar coordinates
Polar regions are swept out like slices of pie. A thin slice with angle ( dtheta ) is nearly a sector of radius r, with area ( frac12r^2,dtheta ). Adding the slices gives
$$A = frac12int_alpha^beta r^2,dtheta = frac12int_alpha^beta [f(theta)]^2,dtheta$$
Example 6: area of the cardioid.
$$A = frac12int_0^{2pi}(1 + costheta)^2,dtheta = frac12int_0^{2pi}left(1 + 2costheta + frac{1 + cos 2theta}{2}right)dtheta = frac12cdot 3pi = frac{3pi}{2}$$
The step that makes ( cos^2theta ) integrable is the power-reducing identity (see trig identities and the integral of sin²x). Check the value in the calculator below, which evaluates ( int_0^{2pi}frac12(1 + cos x)^2,dx ) with x standing for ( theta ):
Step-by-step solver·Exact symbolic engine
Interactive Calculus Problem Solver
Derivatives, antiderivatives, definite and improper integrals, and limits. Every answer comes with the rules used, and antiderivatives are verified by differentiating them back.
Input syntax
- Powers
x^2, rootssqrt(x),cbrt(x), absolute value|x| - Implicit multiplication works:
3x sin(2x) sin cos tan sec csc cot,asin acos atan,sinh cosh tanhe^xorexp(x);ln(x)andlog(x)are both the natural log- Constants
piande; bounds acceptinfand-inf
The answer is ( 4.712389 approx frac{3pi}{2} ).
Example 7: a circle as a check. ( r = 2sintheta ) traces its circle once for ( 0 le theta le pi ): ( A = frac12int_0^pi 4sin^2theta,dtheta = pi ), the area of a circle of radius 1, as it should be.
Area between two polar curves: ( A = frac12int_alpha^beta (r_{text{outer}}^2 – r_{text{inner}}^2),dtheta ), with ( alpha ) and ( beta ) found where the curves meet. Note it’s the difference of the squares, not the square of the difference.
Arc length in polar coordinates
$$L = int_alpha^betasqrt{r^2 + left(frac{dr}{dtheta}right)^2},dtheta$$
For the cardioid ( r = 1 + costheta ), ( r^2 + r’^2 = 2 + 2costheta = 4cos^2frac{theta}{2} ). As a result, the total length works out to exactly 8. Compare this to the rectangular arc length formula.
Where polar coordinates are used
- Physics and astronomy: planetary orbits are conic sections with simple polar equations, ( r = frac{ed}{1 + ecostheta} ).
- Engineering: antenna radiation patterns and microphone pickup patterns (the “cardioid microphone”).
- Navigation: radar and sonar report distance and bearing, a polar description.
- Multivariable calculus: double integrals over circles and rings are far easier in polar form, with ( dA = r,dr,dtheta ) (see double integrals and multivariable calculus).
Common mistakes
- Wrong quadrant for ( theta ). Always check where ( (x, y) ) is before trusting arctan.
- Forgetting the ( frac12 ) and the square in the area formula.
- Integrating over too wide an interval. The equation ( r = 2sintheta ) traces its circle once on ( [0, pi] ); however, integrating to ( 2pi ) doubles the area.
- Squaring the difference for area between curves instead of subtracting squares.
- Degrees in calculus. Polar calculus formulas assume ( theta ) in radians (see degrees to radians).
Practice problems
- Convert ( (4, frac{5pi}{6}) ) to rectangular coordinates.
- Convert ( (0, -3) ) to polar coordinates with ( r > 0 ).
- Convert ( x^2 + y^2 = 9 ) to a polar equation.
- Convert ( r = 6costheta ) to rectangular form and describe the graph.
- How many petals does ( r = sin(3theta) ) have? And ( r = cos(2theta) )?
- Find the area enclosed by ( r = 3 ).
Answers: (1) ( (-2sqrt3, 2) ); (2) ( (3, frac{3pi}{2}) ); (3) ( r = 3 ); (4) ( (x – 3)^2 + y^2 = 9 ), a circle of radius 3 centered at ( (3, 0) ); (5) 3 petals; 4 petals; (6) ( 9pi ).

FAQ
What are polar coordinates?
A way to locate a point by its distance r from the origin and its angle ( theta ) from the positive x-axis, written ( (r, theta) ).
How do you convert polar to rectangular coordinates?
Use ( x = rcostheta ) and ( y = rsintheta ).
How do you convert rectangular to polar coordinates?
Use ( r = sqrt{x^2 + y^2} ) and ( tantheta = frac{y}{x} ), adjusting ( theta ) to the correct quadrant.
What is the formula for area in polar coordinates?
( A = frac12int_alpha^beta r^2,dtheta ).
What is a polar equation?
An equation relating r and ( theta ), usually written ( r = f(theta) ). For example, ( r = 1 + costheta ) is a cardioid and ( r = 2 ) is a circle.
Further reading
- Polar coordinate system (Wikipedia) — conversions, common polar curves and calculus in polar form.
- Calculus II (Paul’s Online Math Notes) — the Parametric Equations and Polar Coordinates chapter, with tangents, area and arc length.
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